\u0110\u1ed1i v\u1edbi nh\u1eefng tay ch\u01a1i l\u00f4 \u0111\u1ec1 <\/strong>chuy\u00ean nghi\u1ec7p th\u00ec l\u00f4 xi\u00ean, l\u00f4 xi\u00ean 2, l\u00f4 xi\u00ean 3 kh\u00f4ng c\u00f2n xa l\u1ea1. Nh\u01b0ng kh\u00f4ng ph\u1ea3i ai c\u0169ng c\u00f3 th\u1ec3 hi\u1ec3u r\u00f5, v\u00e0 c\u00f3 nh\u1eefng c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean<\/strong> ch\u00ednh x\u00e1c v\u00e0 hi\u1ec7u qu\u1ea3 nh\u1ea5t l\u00e0 nh\u01b0 th\u1ebf n\u00e0o. \u0110\u00f3 l\u00e0 l\u00fd do c\u00e1c b\u1ea1n kh\u00f4ng n\u00ean b\u1ecf l\u1ee1 nh\u1eefng th\u00f4ng tin h\u1eefu \u00edch trong b\u00e0i vi\u1ebft ngay sau \u0111\u00e2y.<\/p>\n

H\u00f4m nay \u0111\u00e1nh con g\u00ec \u0111\u1eb9p? N\u00ean \u0111\u00e1nh theo c\u00e1ch n\u00e0o \u0103n ch\u1eafc nh\u1ea5t?<\/strong> \/ B\u1ea1c nh\u1edb l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc \u2013 Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u ch\u00ednh x\u00e1c nh\u1ea5t<\/strong><\/p>\n

L\u00f4 xi\u00ean l\u00e0 g\u00ec? L\u00f4 xi\u00ean 2, 3, 4 l\u00e0 g\u00ec?<\/h2>\n

L\u00f4 xi\u00ean c\u0169ng l\u00e0 m\u1ed9t h\u00ecnh th\u1ee9c ch\u01a1i x\u1ed5 s\u1ed1, l\u00f4 \u0111\u1ec1 c\u00e1 c\u01b0\u1ee3c b\u00ecnh th\u01b0\u1eddng. Tuy nhi\u00ean, kh\u00f4ng gi\u1ed1ng v\u1edbi v\u1edbi vi\u1ec7c ch\u01a1i l\u00f4 th\u00f4ng th\u01b0\u1eddng l\u00e0 ch\u1ec9 \u0111\u00e1nh nh\u1eefng con s\u1ed1 ri\u00eang l\u1ebb, th\u00ec l\u00f4 xi\u00ean l\u1ea1i \u0111\u00e1nh nh\u1eefng c\u1eb7p s\u1ed1, b\u1ed9 ba s\u1ed1, ho\u1eb7c b\u1ed9 4 con s\u1ed1 l\u00f4 li\u1ec1n nhau.\u0110\u00e2y l\u00e0 c\u00e1ch g\u1ecdi t\u01b0\u01a1ng \u1ee9ngv\u1edbi l\u00f4 xi\u00ean 2, l\u00f4 xi\u00ean 3, l\u00f4 xi\u00ean 4 nh\u01b0 tr\u00ean. N\u1ebfu k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 tr\u1ea3 v\u1ec1 c\u00f3 c\u1ea3 2, 3, ho\u1eb7c 4 con l\u00f4 m\u00e0 ch\u00fang ta \u0111\u00e3 \u0111\u00e1nh li\u00ean ti\u1ebfp \u0111\u00f3 th\u00ec s\u1ebd tr\u00fang th\u01b0\u1edfng. N\u1ebfu k\u1ebft qu\u1ea3 s\u1ed5 s\u1ed1 ng\u00e0y h\u00f4m \u0111\u00f3 tr\u1ea3 v\u1ec1 kh\u00f4ng c\u00f3 m\u1ed9t con l\u00f4 b\u1ea5t k\u00ec trong c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean<\/strong> 2, 3, 4 m\u00e0 b\u1ea1n \u0111\u00e3 ch\u01a1i th\u00ec ngh\u0129a l\u00e0 b\u1ea1n s\u1ebd kh\u00f4ng tr\u00fang gi\u1ea3i.<\/p>\n

V\u00ed d\u1ee5 nh\u01b0 n\u1ebfu b\u1ea1n \u0111\u00e1nh l\u00f4 xi\u00ean 2, v\u1edbi 2 con l\u00f4 l\u00e0 25- 02. V\u00e0 trong k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 m\u1edf th\u01b0\u1edfng ng\u00e0y h\u00f4m \u0111\u00f3 cu\u1ed1i c\u00e1c gi\u1ea3i c\u00f3 2 s\u1ed1 25 \u2013 02 th\u00ec b\u1ea1n s\u1ebd th\u1eafng, c\u00f2n n\u1ebfu ch\u1ec9 c\u00f3 1 trong 2 s\u1ed1, ho\u1eb7c kh\u00f4ng c\u00f3 s\u1ed1 n\u00e0o trong gi\u1ea3i th\u00ec k\u1ebft qu\u1ea3 \u0111\u00e1nh l\u00f4 s\u1ebd tr\u01b0\u1ee3t.<\/p>\n

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